d | ρ | Label | ID | ||
---|---|---|---|---|---|
D5×C15 | 30 | 2 | D5xC15 | 150,8 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5⋊(C3×D5) = C3×C5⋊D5 | φ: C3×D5/C15 → C2 ⊆ Aut C5 | 75 | C5:(C3xD5) | 150,9 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5.(C3×D5) = C3×D25 | φ: C3×D5/C15 → C2 ⊆ Aut C5 | 75 | 2 | C5.(C3xD5) | 150,2 |