d | ρ | Label | ID | ||
---|---|---|---|---|---|
Dic3×C15 | 60 | 2 | Dic3xC15 | 180,14 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5⋊(C3×Dic3) = C3×C3⋊F5 | φ: C3×Dic3/C32 → C4 ⊆ Aut C5 | 30 | 4 | C5:(C3xDic3) | 180,21 |
C5⋊2(C3×Dic3) = C3×Dic15 | φ: C3×Dic3/C3×C6 → C2 ⊆ Aut C5 | 60 | 2 | C5:2(C3xDic3) | 180,15 |