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C
n
D
n
S
n
A
n
Degree
Linear
Irr Reps
Characters
×
⋊
.
○
≀
Extensions
1→N→G→Q→1 with N=
C
5
and Q=
CSU
2
(𝔽
3
)
Direct product G=N×Q with N=
C
5
and Q=
CSU
2
(𝔽
3
)
d
ρ
Label
ID
C
5
×CSU
2
(𝔽
3
)
80
2
C5xCSU(2,3)
240,102
Semidirect products G=N:Q with N=
C
5
and Q=
CSU
2
(𝔽
3
)
extension
φ:Q→Aut N
d
ρ
Label
ID
C
5
⋊CSU
2
(𝔽
3
) =
Q
8
.D
15
φ:
CSU
2
(𝔽
3
)
/
SL
2
(𝔽
3
)
→
C
2
⊆ Aut
C
5
80
4-
C5:CSU(2,3)
240,105
×
⋊
ℤ
𝔽
○
≀
ℚ
◁