d | ρ | Label | ID | ||
---|---|---|---|---|---|
C5×Dic14 | 280 | 2 | C5xDic14 | 280,14 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5⋊1Dic14 = C35⋊Q8 | φ: Dic14/Dic7 → C2 ⊆ Aut C5 | 280 | 4- | C5:1Dic14 | 280,13 |
C5⋊2Dic14 = Dic70 | φ: Dic14/C28 → C2 ⊆ Aut C5 | 280 | 2- | C5:2Dic14 | 280,24 |