d | ρ | Label | ID | ||
---|---|---|---|---|---|
S3×C69 | 138 | 2 | S3xC69 | 414,6 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊(S3×C23) = C3⋊S3×C23 | φ: S3×C23/C69 → C2 ⊆ Aut C3 | 207 | C3:(S3xC23) | 414,8 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3.(S3×C23) = D9×C23 | φ: S3×C23/C69 → C2 ⊆ Aut C3 | 207 | 2 | C3.(S3xC23) | 414,1 |