d | ρ | Label | ID | ||
---|---|---|---|---|---|
D4×C57 | 228 | 2 | D4xC57 | 456,40 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(D4×C19) = C19×D12 | φ: D4×C19/C76 → C2 ⊆ Aut C3 | 228 | 2 | C3:1(D4xC19) | 456,31 |
C3⋊2(D4×C19) = C19×C3⋊D4 | φ: D4×C19/C2×C38 → C2 ⊆ Aut C3 | 228 | 2 | C3:2(D4xC19) | 456,33 |