Extensions 1→N→G→Q→1 with N=C₃ and Q=D₂₀.₃C₄

Direct product G=N×Q with N=C₃ and Q=D₂₀.₃C₄

		d	ρ	Label	ID
C₃×D₂₀.₃C₄		240	2	C3xD20.3C4	480,694

Semidirect products G=N:Q with N=C₃ and Q=D₂₀.₃C₄

extension	φ:Q→Aut N	d	ρ	Label	ID
C₃⋊₁(D₂₀.₃C₄) = C₄₀.₅₄D₆	φ: D₂₀.₃C₄/C₈×D₅ → C₂ ⊆ Aut C₃	240	4	C3:1(D20.3C4)	480,341
C₃⋊₂(D₂₀.₃C₄) = C₄₀.₅₅D₆	φ: D₂₀.₃C₄/C₈⋊D₅ → C₂ ⊆ Aut C₃	240	4	C3:2(D20.3C4)	480,343
C₃⋊₃(D₂₀.₃C₄) = D₆₀.₄C₄	φ: D₂₀.₃C₄/C₄.Dic₅ → C₂ ⊆ Aut C₃	240	4	C3:3(D20.3C4)	480,367
C₃⋊₄(D₂₀.₃C₄) = D₆₀.₆C₄	φ: D₂₀.₃C₄/C₂×C₄₀ → C₂ ⊆ Aut C₃	240	2	C3:4(D20.3C4)	480,866
C₃⋊₅(D₂₀.₃C₄) = D₂₀.₃Dic₃	φ: D₂₀.₃C₄/C₄○D₂₀ → C₂ ⊆ Aut C₃	240	4	C3:5(D20.3C4)	480,359

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