d | ρ | Label | ID | ||
---|---|---|---|---|---|
C3×C4.Dic5 | 120 | 2 | C3xC4.Dic5 | 240,39 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(C4.Dic5) = D6.Dic5 | φ: C4.Dic5/C5⋊2C8 → C2 ⊆ Aut C3 | 120 | 4 | C3:1(C4.Dic5) | 240,11 |
C3⋊2(C4.Dic5) = C60.7C4 | φ: C4.Dic5/C2×C20 → C2 ⊆ Aut C3 | 120 | 2 | C3:2(C4.Dic5) | 240,71 |