extension | φ:Q→Out N | d | ρ | Label | ID |
D5⋊M4(2)⋊1C2 = (D4×C10)⋊C4 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 40 | 8+ | D5:M4(2):1C2 | 320,1105 |
D5⋊M4(2)⋊2C2 = (C2×D4)⋊6F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8- | D5:M4(2):2C2 | 320,1107 |
D5⋊M4(2)⋊3C2 = D5⋊(C4.D4) | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 40 | 8+ | D5:M4(2):3C2 | 320,1116 |
D5⋊M4(2)⋊4C2 = (C2×Q8)⋊6F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8+ | D5:M4(2):4C2 | 320,1122 |
D5⋊M4(2)⋊5C2 = D5⋊C4≀C2 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 40 | 8 | D5:M4(2):5C2 | 320,1130 |
D5⋊M4(2)⋊6C2 = C4○D4⋊F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 40 | 8 | D5:M4(2):6C2 | 320,1131 |
D5⋊M4(2)⋊7C2 = Dic5.C24 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8- | D5:M4(2):7C2 | 320,1594 |
D5⋊M4(2)⋊8C2 = Dic5.20C24 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8+ | D5:M4(2):8C2 | 320,1598 |
D5⋊M4(2)⋊9C2 = Dic5.21C24 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8 | D5:M4(2):9C2 | 320,1601 |
D5⋊M4(2)⋊10C2 = Dic5.22C24 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8 | D5:M4(2):10C2 | 320,1602 |
D5⋊M4(2)⋊11C2 = (C4×D5).D4 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 4 | D5:M4(2):11C2 | 320,1099 |
extension | φ:Q→Out N | d | ρ | Label | ID |
D5⋊M4(2).1C2 = M4(2)⋊F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 40 | 8 | D5:M4(2).1C2 | 320,237 |
D5⋊M4(2).2C2 = M4(2).F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8 | D5:M4(2).2C2 | 320,239 |
D5⋊M4(2).3C2 = M4(2)×F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 40 | 8 | D5:M4(2).3C2 | 320,1064 |
D5⋊M4(2).4C2 = M4(2).1F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8 | D5:M4(2).4C2 | 320,1067 |
D5⋊M4(2).5C2 = (C2×Q8)⋊4F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8- | D5:M4(2).5C2 | 320,1120 |
D5⋊M4(2).6C2 = (C2×Q8).7F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 8- | D5:M4(2).6C2 | 320,1127 |
D5⋊M4(2).7C2 = C42⋊6F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 40 | 4 | D5:M4(2).7C2 | 320,200 |
D5⋊M4(2).8C2 = C42⋊3F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 4 | D5:M4(2).8C2 | 320,201 |
D5⋊M4(2).9C2 = (C2×C8)⋊F5 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 4 | D5:M4(2).9C2 | 320,232 |
D5⋊M4(2).10C2 = C20.25C42 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 4 | D5:M4(2).10C2 | 320,235 |
D5⋊M4(2).11C2 = (C8×D5).C4 | φ: C2/C1 → C2 ⊆ Out D5⋊M4(2) | 80 | 4 | D5:M4(2).11C2 | 320,1062 |
D5⋊M4(2).12C2 = C20.12C42 | φ: trivial image | 80 | 4 | D5:M4(2).12C2 | 320,1056 |