d | ρ | Label | ID | ||
---|---|---|---|---|---|
D5×C39 | 195 | 2 | D5xC39 | 390,6 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C13⋊(C3×D5) = D65⋊C3 | φ: C3×D5/C5 → C6 ⊆ Aut C13 | 65 | 6+ | C13:(C3xD5) | 390,3 |
C13⋊2(C3×D5) = D5×C13⋊C3 | φ: C3×D5/D5 → C3 ⊆ Aut C13 | 65 | 6 | C13:2(C3xD5) | 390,2 |
C13⋊3(C3×D5) = C3×D65 | φ: C3×D5/C15 → C2 ⊆ Aut C13 | 195 | 2 | C13:3(C3xD5) | 390,7 |