d | ρ | Label | ID | ||
---|---|---|---|---|---|
D5×C42 | 210 | 2 | D5xC42 | 420,35 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(D5×C14) = S3×C7×D5 | φ: D5×C14/C7×D5 → C2 ⊆ Aut C3 | 105 | 4 | C3:1(D5xC14) | 420,27 |
C3⋊2(D5×C14) = C14×D15 | φ: D5×C14/C70 → C2 ⊆ Aut C3 | 210 | 2 | C3:2(D5xC14) | 420,39 |