d | ρ | Label | ID | ||
---|---|---|---|---|---|
C15×Dic7 | 420 | 2 | C15xDic7 | 420,5 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5⋊(C3×Dic7) = C3×C7⋊F5 | φ: C3×Dic7/C21 → C4 ⊆ Aut C5 | 105 | 4 | C5:(C3xDic7) | 420,21 |
C5⋊2(C3×Dic7) = C3×Dic35 | φ: C3×Dic7/C42 → C2 ⊆ Aut C5 | 420 | 2 | C5:2(C3xDic7) | 420,7 |