Extensions 1→N→G→Q→1 with N=D₁₅ and Q=M₄(2)

Direct product G=N×Q with N=D₁₅ and Q=M₄(2)

		d	ρ	Label	ID
M₄(2)×D₁₅		120	4	M4(2)xD15	480,871

Semidirect products G=N:Q with N=D₁₅ and Q=M₄(2)

extension	φ:Q→Out N	d	ρ	Label	ID
D₁₅⋊₁M₄(2) = D₁₅⋊M₄(2)	φ: M₄(2)/C₄ → C₄ ⊆ Out D₁₅	120	8	D15:1M4(2)	480,991
D₁₅⋊₂M₄(2) = D₁₅⋊₂M₄(2)	φ: M₄(2)/C₂² → C₄ ⊆ Out D₁₅	120	8+	D15:2M4(2)	480,1007
D₁₅⋊₃M₄(2) = C₄₀⋊D₆	φ: M₄(2)/C₈ → C₂ ⊆ Out D₁₅	120	4	D15:3M4(2)	480,322
D₁₅⋊₄M₄(2) = D₁₅⋊₄M₄(2)	φ: M₄(2)/C₂×C₄ → C₂ ⊆ Out D₁₅	120	4	D15:4M4(2)	480,368

׿

×

⋊

ℤ

𝔽

○

≀

ℚ

◁