d | ρ | Label | ID | ||
---|---|---|---|---|---|
D4×C51 | 204 | 2 | D4xC51 | 408,31 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(D4×C17) = C17×D12 | φ: D4×C17/C68 → C2 ⊆ Aut C3 | 204 | 2 | C3:1(D4xC17) | 408,22 |
C3⋊2(D4×C17) = C17×C3⋊D4 | φ: D4×C17/C2×C34 → C2 ⊆ Aut C3 | 204 | 2 | C3:2(D4xC17) | 408,24 |