d | ρ | Label | ID | ||
---|---|---|---|---|---|
C3×Dic5.D4 | 240 | 4 | C3xDic5.D4 | 480,285 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(Dic5.D4) = Dic5.4D12 | φ: Dic5.D4/C22.F5 → C2 ⊆ Aut C3 | 240 | 8- | C3:1(Dic5.D4) | 480,251 |
C3⋊2(Dic5.D4) = (C2×C60).C4 | φ: Dic5.D4/C2×Dic10 → C2 ⊆ Aut C3 | 240 | 4 | C3:2(Dic5.D4) | 480,310 |