d | ρ | Label | ID | ||
---|---|---|---|---|---|
C6×F5 | 30 | 4 | C6xF5 | 120,40 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(C2×F5) = S3×F5 | φ: C2×F5/F5 → C2 ⊆ Aut C3 | 15 | 8+ | C3:1(C2xF5) | 120,36 |
C3⋊2(C2×F5) = C2×C3⋊F5 | φ: C2×F5/D10 → C2 ⊆ Aut C3 | 30 | 4 | C3:2(C2xF5) | 120,41 |