d | ρ | Label | ID | ||
---|---|---|---|---|---|
C5×C13⋊C4 | 65 | 4 | C5xC13:C4 | 260,5 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5⋊1(C13⋊C4) = C13⋊F5 | φ: C13⋊C4/C13 → C4 ⊆ Aut C5 | 65 | 4+ | C5:1(C13:C4) | 260,9 |
C5⋊2(C13⋊C4) = C65⋊2C4 | φ: C13⋊C4/C13 → C4 ⊆ Aut C5 | 65 | 4+ | C5:2(C13:C4) | 260,10 |
C5⋊3(C13⋊C4) = C65⋊C4 | φ: C13⋊C4/D13 → C2 ⊆ Aut C5 | 65 | 4 | C5:3(C13:C4) | 260,6 |