d | ρ | Label | ID | ||
---|---|---|---|---|---|
D4×C39 | 156 | 2 | D4xC39 | 312,43 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(D4×C13) = C13×D12 | φ: D4×C13/C52 → C2 ⊆ Aut C3 | 156 | 2 | C3:1(D4xC13) | 312,34 |
C3⋊2(D4×C13) = C13×C3⋊D4 | φ: D4×C13/C2×C26 → C2 ⊆ Aut C3 | 156 | 2 | C3:2(D4xC13) | 312,36 |