d | ρ | Label | ID | ||
---|---|---|---|---|---|
C5×C4⋊1D4 | 80 | C5xC4:1D4 | 160,188 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5⋊1(C4⋊1D4) = C20⋊4D4 | φ: C4⋊1D4/C42 → C2 ⊆ Aut C5 | 80 | C5:1(C4:1D4) | 160,95 | |
C5⋊2(C4⋊1D4) = C20⋊D4 | φ: C4⋊1D4/C2×D4 → C2 ⊆ Aut C5 | 80 | C5:2(C4:1D4) | 160,161 |