d | ρ | Label | ID | ||
---|---|---|---|---|---|
C3×C4⋊Dic5 | 240 | C3xC4:Dic5 | 240,42 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(C4⋊Dic5) = C6.Dic10 | φ: C4⋊Dic5/C2×Dic5 → C2 ⊆ Aut C3 | 240 | C3:1(C4:Dic5) | 240,31 | |
C3⋊2(C4⋊Dic5) = C60⋊5C4 | φ: C4⋊Dic5/C2×C20 → C2 ⊆ Aut C3 | 240 | C3:2(C4:Dic5) | 240,74 |