d | ρ | Label | ID | ||
---|---|---|---|---|---|
D4×C33 | 132 | 2 | D4xC33 | 264,29 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(D4×C11) = C11×D12 | φ: D4×C11/C44 → C2 ⊆ Aut C3 | 132 | 2 | C3:1(D4xC11) | 264,20 |
C3⋊2(D4×C11) = C11×C3⋊D4 | φ: D4×C11/C2×C22 → C2 ⊆ Aut C3 | 132 | 2 | C3:2(D4xC11) | 264,22 |