d | ρ | Label | ID | ||
---|---|---|---|---|---|
SD16×C31 | 248 | 2 | SD16xC31 | 496,25 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C31⋊1SD16 = C248⋊C2 | φ: SD16/C8 → C2 ⊆ Aut C31 | 248 | 2 | C31:1SD16 | 496,5 |
C31⋊2SD16 = D4.D31 | φ: SD16/D4 → C2 ⊆ Aut C31 | 248 | 4- | C31:2SD16 | 496,15 |
C31⋊3SD16 = Q8⋊D31 | φ: SD16/Q8 → C2 ⊆ Aut C31 | 248 | 4+ | C31:3SD16 | 496,16 |