d | ρ | Label | ID | ||
---|---|---|---|---|---|
C3×C4.Dic7 | 168 | 2 | C3xC4.Dic7 | 336,64 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C3⋊1(C4.Dic7) = D6.Dic7 | φ: C4.Dic7/C7⋊C8 → C2 ⊆ Aut C3 | 168 | 4 | C3:1(C4.Dic7) | 336,27 |
C3⋊2(C4.Dic7) = C84.C4 | φ: C4.Dic7/C2×C28 → C2 ⊆ Aut C3 | 168 | 2 | C3:2(C4.Dic7) | 336,96 |