Extensions 1→N→G→Q→1 with N=D10⋊C4 and Q=S3

Direct product G=N×Q with N=D10⋊C4 and Q=S3
dρLabelID
S3×D10⋊C4120S3xD10:C4480,548

Semidirect products G=N:Q with N=D10⋊C4 and Q=S3
extensionφ:Q→Out NdρLabelID
D10⋊C41S3 = Dic3.D20φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:1S3480,429
D10⋊C42S3 = D10⋊C4⋊S3φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:2S3480,528
D10⋊C43S3 = D6⋊D20φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:3S3480,530
D10⋊C44S3 = D10.17D12φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:4S3480,490
D10⋊C45S3 = D6.9D20φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:5S3480,533
D10⋊C46S3 = D302D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:6S3480,535
D10⋊C47S3 = Dic15.10D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:7S3480,538
D10⋊C48S3 = D305D4φ: S3/C3C2 ⊆ Out D10⋊C4120D10:C4:8S3480,552
D10⋊C49S3 = D30.34D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:9S3480,430
D10⋊C410S3 = Dic1513D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:10S3480,472
D10⋊C411S3 = Dic159D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:11S3480,518
D10⋊C412S3 = D3012D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:12S3480,537
D10⋊C413S3 = Dic15.31D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:13S3480,540
D10⋊C414S3 = D30.27D4φ: S3/C3C2 ⊆ Out D10⋊C4120D10:C4:14S3480,549
D10⋊C415S3 = D30.D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:15S3480,432
D10⋊C416S3 = D10.16D12φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:16S3480,489
D10⋊C417S3 = Dic152D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:17S3480,529
D10⋊C418S3 = (C2×Dic6)⋊D5φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4:18S3480,531
D10⋊C419S3 = D304D4φ: S3/C3C2 ⊆ Out D10⋊C4120D10:C4:19S3480,551
D10⋊C420S3 = Dic34D20φ: trivial image240D10:C4:20S3480,471
D10⋊C421S3 = C1517(C4×D4)φ: trivial image240D10:C4:21S3480,517

Non-split extensions G=N.Q with N=D10⋊C4 and Q=S3
extensionφ:Q→Out NdρLabelID
D10⋊C4.1S3 = (C4×Dic3)⋊D5φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.1S3480,439
D10⋊C4.2S3 = (C2×C60).C22φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.2S3480,438
D10⋊C4.3S3 = D102Dic6φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.3S3480,498
D10⋊C4.4S3 = D104Dic6φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.4S3480,507
D10⋊C4.5S3 = (C4×Dic15)⋊C2φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.5S3480,442
D10⋊C4.6S3 = D10.19(C4×S3)φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.6S3480,470
D10⋊C4.7S3 = (C2×C12).D10φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.7S3480,437
D10⋊C4.8S3 = D101Dic6φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.8S3480,497
D10⋊C4.9S3 = Dic15.D4φ: S3/C3C2 ⊆ Out D10⋊C4240D10:C4.9S3480,506
D10⋊C4.10S3 = (D5×Dic3)⋊C4φ: trivial image240D10:C4.10S3480,469

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