d | ρ | Label | ID | ||
---|---|---|---|---|---|
C5×Dic25 | 100 | 2 | C5xDic25 | 500,6 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5⋊Dic25 = D5.D25 | φ: Dic25/C25 → C4 ⊆ Aut C5 | 100 | 4 | C5:Dic25 | 500,19 |
C5⋊2Dic25 = C50.D5 | φ: Dic25/C50 → C2 ⊆ Aut C5 | 500 | C5:2Dic25 | 500,10 |
extension | φ:Q→Aut N | d | ρ | Label | ID |
---|---|---|---|---|---|
C5.Dic25 = Dic125 | φ: Dic25/C50 → C2 ⊆ Aut C5 | 500 | 2- | C5.Dic25 | 500,1 |