Home
About
Cn
Dn
Sn
An
Degree
Linear
Irr Reps
Characters
×
⋊
.
○
≀

Extensions 1→N→G→Q→1 with N=D4 and Q=S3×D5

Direct product G=N×Q with N=D4 and Q=S3×D5
dρLabelID
S3×D4×D5608+S3xD4xD5480,1097

Semidirect products G=N:Q with N=D4 and Q=S3×D5
extensionφ:Q→Out NdρLabelID
D4⋊1(S3×D5) = S3×D4⋊D5φ: S3×D5/C5×S3 → C2 ⊆ Out D41208+D4:1(S3xD5)480,555
D4⋊2(S3×D5) = D60.C22φ: S3×D5/C5×S3 → C2 ⊆ Out D41208+D4:2(S3xD5)480,556
D4⋊3(S3×D5) = D5×D4⋊S3φ: S3×D5/C3×D5 → C2 ⊆ Out D41208+D4:3(S3xD5)480,553
D4⋊4(S3×D5) = Dic10⋊3D6φ: S3×D5/C3×D5 → C2 ⊆ Out D41208+D4:4(S3xD5)480,554
D4⋊5(S3×D5) = D15⋊D8φ: S3×D5/D15 → C2 ⊆ Out D41208+D4:5(S3xD5)480,557
D4⋊6(S3×D5) = D30.8D4φ: S3×D5/D15 → C2 ⊆ Out D41208-D4:6(S3xD5)480,558
D4⋊7(S3×D5) = D5×D4⋊2S3φ: trivial image1208-D4:7(S3xD5)480,1098
D4⋊8(S3×D5) = S3×D4⋊2D5φ: trivial image1208-D4:8(S3xD5)480,1099
D4⋊9(S3×D5) = D30.C23φ: trivial image1208+D4:9(S3xD5)480,1100
D4⋊10(S3×D5) = D20⋊13D6φ: trivial image1208-D4:10(S3xD5)480,1101
D4⋊11(S3×D5) = D20⋊14D6φ: trivial image1208+D4:11(S3xD5)480,1102
D4⋊12(S3×D5) = D12⋊14D10φ: trivial image1208+D4:12(S3xD5)480,1103

Non-split extensions G=N.Q with N=D4 and Q=S3×D5
extensionφ:Q→Out NdρLabelID
D4.1(S3×D5) = S3×D4.D5φ: S3×D5/C5×S3 → C2 ⊆ Out D41208-D4.1(S3xD5)480,561
D4.2(S3×D5) = C60.10C23φ: S3×D5/C5×S3 → C2 ⊆ Out D42408-D4.2(S3xD5)480,562
D4.3(S3×D5) = D20.24D6φ: S3×D5/C5×S3 → C2 ⊆ Out D42408-D4.3(S3xD5)480,569
D4.4(S3×D5) = D20⋊10D6φ: S3×D5/C5×S3 → C2 ⊆ Out D41208-D4.4(S3xD5)480,570
D4.5(S3×D5) = C60.19C23φ: S3×D5/C5×S3 → C2 ⊆ Out D42408+D4.5(S3xD5)480,571
D4.6(S3×D5) = D12.9D10φ: S3×D5/C5×S3 → C2 ⊆ Out D41208+D4.6(S3xD5)480,572
D4.7(S3×D5) = D5×D4.S3φ: S3×D5/C3×D5 → C2 ⊆ Out D41208-D4.7(S3xD5)480,559
D4.8(S3×D5) = C60.8C23φ: S3×D5/C3×D5 → C2 ⊆ Out D42408-D4.8(S3xD5)480,560
D4.9(S3×D5) = D12⋊10D10φ: S3×D5/C3×D5 → C2 ⊆ Out D41208-D4.9(S3xD5)480,565
D4.10(S3×D5) = D12.24D10φ: S3×D5/C3×D5 → C2 ⊆ Out D42408-D4.10(S3xD5)480,566
D4.11(S3×D5) = D20.9D6φ: S3×D5/C3×D5 → C2 ⊆ Out D41208+D4.11(S3xD5)480,567
D4.12(S3×D5) = C60.16C23φ: S3×D5/C3×D5 → C2 ⊆ Out D42408+D4.12(S3xD5)480,568
D4.13(S3×D5) = Dic10⋊D6φ: S3×D5/D15 → C2 ⊆ Out D41208+D4.13(S3xD5)480,563
D4.14(S3×D5) = D30.9D4φ: S3×D5/D15 → C2 ⊆ Out D42408-D4.14(S3xD5)480,564
D4.15(S3×D5) = D20.10D6φ: S3×D5/D15 → C2 ⊆ Out D42408-D4.15(S3xD5)480,573
D4.16(S3×D5) = Dic6⋊D10φ: S3×D5/D15 → C2 ⊆ Out D41208+D4.16(S3xD5)480,574
D4.17(S3×D5) = D30.11D4φ: S3×D5/D15 → C2 ⊆ Out D42408-D4.17(S3xD5)480,575
D4.18(S3×D5) = D12⋊5D10φ: S3×D5/D15 → C2 ⊆ Out D41208+D4.18(S3xD5)480,576
D4.19(S3×D5) = C15⋊2- 1+4φ: trivial image2408-D4.19(S3xD5)480,1096

׿
×
⋊
ℤ
𝔽
○
≀
ℚ
◁